(-5/y)^2

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Solution for (-5/y)^2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(-5/y)^2 = 0

25*y^-2 = 0 // : 25

y^-2 = 0

y naleu017Cy do O

y belongs to the empty set

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